32x^2-12x=35

Solution for 32x^2-12x=35 equation:

32x^2-12x=35

We move all terms to the left:

32x^2-12x-(35)=0

a = 32; b = -12; c = -35;
Δ = b2-4ac
Δ = -122-4·32·(-35)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-68}{2*32}=\frac{-56}{64}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+68}{2*32}=\frac{80}{64}
=1+1/4
$